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Question

Mathematics Question on Logic gates

The statement (p∨(∼q))∧(∼p)(p \vee (\sim q)) \wedge (\sim p) is equivalent to?

A

p∧qp \wedge q

B

∼p∨∼q\sim p \vee \sim q

C

p∨qp \vee q

D

∼p∧∼q\sim p \wedge \sim q

Answer

∼p∨∼q\sim p \vee \sim q

Explanation

Solution

The correct option is (B): ∼p∨∼q\sim p \vee \sim q