Question

The statement $(p \Rightarrow q ) \Leftrightarrow ( \sim p \Lambda q)$ is a

• A. tautology
• B. contradiction
• C. Neither (a) nor (b)
• D. None of these

Answer 1

Answer: (C)

Neither (a) nor (b)

Answer 2

$p$
| $q$
| $p$
| $p \Rightarrow q$
| $\sim p \wedge q$
| $(p \Rightarrow q) \Leftrightarrow ( \sim p \wedge q)$

---|---|---|---|---|---

T
| T
| F
| T
| F
| F

T
| F
| F
| F
| F
| T

F
| T
| T
| T
| T
| T

F
| F
| T
| T
| F
| F

Hence, given statement is neither tautology nor contradiction .