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Chemistry Question on Electrochemistry

The standard reduction potentials at 298K for the following half cells are given : Zn2+(aq)+2e−⇌Zn(s); E∘=−0.762 VZn^{2+}(aq)+2e^- \rightleftharpoons Zn(s);\, E^\circ = -0.762\, V Cr3+(aq)+3e−⇌Cr(s); E∘=−0.740 VCr^{3+}(aq)+3e^- \rightleftharpoons Cr(s);\, E^\circ = -0.740\, V 2H+(aq)+2e−⇌H2(g); E∘=−0.000 V2H^{+}(aq)+2e^- \rightleftharpoons H_2(g);\, E^\circ = -0.000\, V    Fe3+(aq)+e−⇌Fe2+(aq); E∘=−0.770 V\, \, \, Fe^{3+}(aq)+e^- \rightleftharpoons Fe^{2+} (aq);\, E^\circ = -0.770\, V

A

Zn(s)

B

Cr(s)

C

H2(g)H_2 (g)

D

Fe2+(aq)Fe^{2+}(aq)

Answer

Zn(s)

Explanation

Solution

Lower the value of E∘E^\circ, stronger the reducing agent.