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Physical Chemistry Question on Thermodynamics

The standard Gibbs free energy change for the reaction
H2O(g)→H2(g)+½O2(g)H_2O (g) → H_2 (g) + ½ O_2(g) at 2500 K is +118kJmol−1+118 kJ mol^{-1}
The equilibrium constant for the reaction is
[Given: R=8.314JK−1mol−1R= 8.314 J K^{-1} mol^{-1}]

A

0.994

B

1.006

C

3.42 x 10−310^{-3}

D

292.12

Answer

3.42 x 10−310^{-3}

Explanation

Solution

The correct option is (C): 3.42 x 10−310^{-3}