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Question

Chemistry Question on Equilibrium

The standard Gibbs energy change at 300K300 \,K for the reaction 2AB+C2 A \to B+C is 2494.2]2494.2]. At a given time, the composition of the reaction mixture is [A]=12,[B]=2[ A ]=\frac{1}{2},[ B ]=2 and [C]=12.[ C ] =\frac{1}{2} . The reaction proceeds in the : [R=8.314J/K/mol,e=2.718][ R =8.314\, J / \,K /\, mol , e =2.718]

A

forward direction because Q>KcQ > K_c

B

reverse direction because Q>Kc Q> K_c

C

forward direction because Q<KcQ < K_c

D

reverse direction because Q<KcQ < K_c

Answer

reverse direction because Q>Kc Q> K_c

Explanation

Solution

ΔG\Delta G^{\circ} at 300K=2494.2J300\, K =2494.2 \,J
ΔG0=RTnK\Delta G ^{0}=- RT \ell n K
2494.2=8.314×300nK-2494.2=-8.314 \times 300 \,\ell\, n\, K
K=10K =10
Q=[B][C][A]2=2×12(12)2=4Q =\frac{[ B ][ C ]}{[ A ]^{2}}=\frac{2 \times \frac{1}{2}}{\left(\frac{1}{2}\right)^{2}}=4
Q>KcQ > K _{ c } \Rightarrow reverse direction.