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Chemistry Question on Equilibrium

The standard entropy change for the reaction 4Fe(s)+3O2(g)2Fe2O3(s)4Fe(s) + 3O_2(g) → 2Fe_2O_3(s) is 550 JK1–550\ J K^{–1} at 298 K298\ K. The temperature in K at which the reaction attains equilibrium is ______. (Nearest Integer)
[Given: The standard enthalpy change for the reaction is 165 kJmol1–165\ kJmol^{–1}].

Answer

S=HT∵ △S =\frac {△H}{T}
So, the temperature at which the reaction attains equilibrium,
T=HST = \frac {△H}{△S}

T=165×103550T= \frac {165\times 10^3}{550}

T=300 KT= 300\ K

So, the answer is 300 K300\ K.