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Chemistry Question on Redox reactions

The standard emf of a galvanic cell involving 33 moles of electrons in its redox reaction is 0.59 V0.59 \,V. The equilibrium constant for the reaction of the cell is

A

102010^{20}

B

102510^{25}

C

103010^{30}

D

101510^{15}

Answer

103010^{30}

Explanation

Solution

Ecell ∘=0.0591nlog⁡KcE_{\text {cell }}^{\circ} =\frac{0.0591}{n} \log K_{c} 0.59=0.05913log⁡Kc 0.59×30.059=log⁡Kc0.59 =\frac{0.0591}{3} \log K_{c} \\\ \frac{0.59 \times 3}{0.059} =\log K_{c} ∴log⁡Kc=30\therefore \log K_{c} =30 Kc=K_{c} = antilog 3030 =1030=10^{30}