Question

The standard emf of a cell involving one electron charge is found to be $0.591\, V$ at $25^{\circ} C$. The equilibrium constant of the reaction is $\left(1\, F =96500\, C\, mol ^{-1}, R=8.314\, J\, K ^{-1} mol ^{-1}\right)$

• A. $1.0\times 10^{1}$
• B. $1.0\times 10^{30}$
• C. $1.0\times 10^{10}$
• D. $1.0\times 10^{5}$

Answer 1

Answer: (C)

$1.0\times 10^{10}$

Answer 2

At $298\, K$ $E^{\circ} =\frac{0.0591}{n} \log K_{c}$ $0.591 =\frac{0.0591}{1} \log K_{c}$ $\log K_{c} =\frac{0.5910}{0.0591}$ $\log K_{c} =10$ $K_{c} =10^{10}$