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Question

Chemistry Question on Nernst Equation

The standard electrode potentials of Ag+/AgA{{g}^{+}}/Ag is +0.80 V+0.80\text{ }V and Cu+/CuC{{u}^{+}}/Cu is +0.34 V+0.34\text{ }V . These electrodes are connected through a salt bridge and if:

A

copper electrode acts as a cathode then EE{}^\circ cell is +0.46 V+0.46\text{ }V

B

silver electrode acts as anode then EE{}^\circ cell is 0.34 V-0.34\text{ }V

C

copper electrode acts as anode then EE{}^\circ cell is +0.46V+0.46V

D

silver electrode acts as a cathode then EE{}^\circ cell is 0.34 V-0.34\text{ }V

Answer

copper electrode acts as anode then EE{}^\circ cell is +0.46V+0.46V

Explanation

Solution

Ecello=EcathodeoEanodeoE_{cell}^{o}=E_{cathode}^{o}-E_{anode}^{o}
=EAg+/AgoECu+/Cuo=E_{A{{g}^{+}}/Ag}^{o}-E_{C{{u}^{+}}/Cu}^{o}
=0.800.34=-0.80-0.34
=+0.46=+0.46