Solveeit Logo

Question

Inorganic Chemistry Question on Chemical bonding and molecular structure

The stability of adducts H3B.PF3,H3B.NMc3,H3B.CO,H3B.OMe2H_3B.PF_3, H_3B.NMc_3, H_3B.CO, H_3B.OMe_2 follows the order

A

H3B.OMe2<H3B.CO<H3BPF3<H3B.NMc3H_3B.OMe_2 < H_3B.CO < H_3B-PF_3 < H_3B.NMc_3

B

H3B.PF3,<H3B.CO<H3B.NMc3<H3B.OMe2H_3B.PF_3,< H_3B.CO < H_3B.NMc_3 < H_3B.OMe_2

C

H3B.CO<H3B.PF3,<H3B.NMc3<H3B.OMe2H_3B.CO < H_3B.PF_3, < H_3B.NMc_3 < H_3B.OMe_2

D

H3B.PF3,<H3B.CO<H3B.OMe2<H3B.NMc3H_3B.PF_3, < H_3B.CO < H_3B.OMe_2 < H_3B.NMc_3

Answer

H3B.PF3,<H3B.CO<H3B.OMe2<H3B.NMc3H_3B.PF_3, < H_3B.CO < H_3B.OMe_2 < H_3B.NMc_3

Explanation

Solution

The correct option is (D): H3B.PF3,<H3B.CO<H3B.OMe2<H3B.NMc3H_3B.PF_3, < H_3B.CO < H_3B.OMe_2 < H_3B.NMc_3