Question
Question: The square root of \(\therefore\)is....
The square root of ∴is.
A
A(x2+1)+(Bx+C)x=1
B
x=0
C
A=1
D
x=i
Answer
x=i
Explanation
Solution
=log22+4=1+4=5
= log1000x2=log103x2=2log103x=32log10x=32y; x=logabc ⇒.
The square root of ∴is.
A(x2+1)+(Bx+C)x=1
x=0
A=1
x=i
x=i
=log22+4=1+4=5
= log1000x2=log103x2=2log103x=32log10x=32y; x=logabc ⇒.