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Question

Question: The square root of \(\therefore\)is....

The square root of \thereforeis.

A

A(x2+1)+(Bx+C)x=1A(x^{2} + 1) + (Bx + C)x = 1

B

x=0x = 0

C

A=1A = 1

D

x=ix = i

Answer

x=ix = i

Explanation

Solution

=log22+4=1+4=5= \log_{2}2 + 4 = 1 + 4 = 5

= log1000x2=log103x2=2log103x=23log10x=23y\log_{1000}x^{2} = \log_{10^{3}}x^{2} = 2\log_{10^{3}}x = \frac{2}{3}\log_{10}x = \frac{2}{3}y; x=logabcx = \log_{a}bc \Rightarrow.