The square root of (3 - 4i) are | MATH - SQUARE ROOT, REPRESENTATION AND LOGARITHM OF COMPLEX NUMBERS | SolveeIt

The square root of $3 - 4i$ are

$\pm (2 - i)$

$\pm (2 + i)$

$\pm (\sqrt{3} - 2i)$

$\pm (\sqrt{3} + 2i)$

Answer

$\pm (2 - i)$

Explanation

Sol. $|z| = 5,\therefore\sqrt{3 - 4i} = \pm \left( \sqrt{\frac{5 + 3}{2}} - i\sqrt{\frac{5 - 3}{2}} \right) = \pm (2 - i)$

Question: The square root of \(3 - 4i\) are...