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Question: The square of the length of the tangent from (3, – 4) on the circle x<sup>2</sup>+y<sup>2</sup>–4x...

The square of the length of the tangent from
(3, – 4) on the circle x2+y2–4x – 6y + 3 = 0 is –

A

20

B

30

C

40

D

50

Answer

40

Explanation

Solution

Length of tangent = S1\sqrt { \mathrm { S } _ { 1 } }

length)2 = S1 = 9 + 16 – 12 + 24 + 3 = 40