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Question: The spring block system lies on a smooth horizontal surface. The free end of the spring is being pul...

The spring block system lies on a smooth horizontal surface. The free end of the spring is being pulled towards right with constant speed V0 = 2m/s. At t = 0 sec, the spring of constant

k = 100 N/cm is unstreched and the block has a speed 1 m/s to left. The maximum extension of the spring is –

A

2cm

B

4 cm

C

6 cm

D

8 cm

Answer

6 cm

Explanation

Solution

In the frame (inertial w.r.t. earth) of free end of spring, the initial velocity of block is 3m/s to left and the spring unstreched.

Applying conservation of energy between initial and

maximum extension state.

12\frac { 1 } { 2 } mV2 = 12\frac { 1 } { 2 } kA2

A = mk\sqrt { \frac { \mathrm { m } } { \mathrm { k } } } V

41000\sqrt { \frac { 4 } { 1000 } } × 3 = 6 cm.