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Question

Chemistry Question on Coordination chemistry

The 'spin only' magnetic moment value of MO42MO_4^{2-} is ____ BM\text{BM}. (Where MM is a metal having least metallic radii among Sc, Ti, V, Cr, Mn, Zn\text{Sc, Ti, V, Cr, Mn, Zn}). [Given atomic number: Sc = 21, Ti = 22, V = 23, Cr = 24, Mn = 25, Zn = 30][ \text{Given atomic number: Sc = 21, Ti = 22, V = 23, Cr = 24, Mn = 25, Zn = 30} ]

Answer

Among the given elements, Cr has the least metallic radii. The CrO42_4^{2-} ion has Cr6+^{6+}, which has a d0d^0 configuration (diamagnetic).
The spin-only magnetic moment:
μ=n(n+2)BM,\mu = \sqrt{n(n+2)} \, \text{BM},
where n=0n = 0.
Final Answer:
0BM.0 \, \text{BM}.

Explanation

Solution

Among the given elements, Cr has the least metallic radii. The CrO42_4^{2-} ion has Cr6+^{6+}, which has a d0d^0 configuration (diamagnetic).
The spin-only magnetic moment:
μ=n(n+2)BM,\mu = \sqrt{n(n+2)} \, \text{BM},
where n=0n = 0.
Final Answer:
0BM.0 \, \text{BM}.