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Question

Chemistry Question on coordination compounds

The spin-only magnetic moment of [crF6]4\left[crF_{6}\right]^{4-} (atomic number of Cr is 24) is

A

0

B

1.73 BM

C

2.83 BM

D

4.9 BM

Answer

4.9 BM

Explanation

Solution

24Cr=[Ar]3d54s1,Cr2+_{24}Cr=\left[Ar \right]3d^{5} 4s^{1}, Cr^{2+}
F- is a weak field ligand, 0<P,Nopairing\bigtriangleup_{0} < P, No \,\, pairing
[CrF6]4=\left[CrF_{6}\right]^{-4}=
No. of unpaired e\overline{e} =4, Spin only magnetic moment (μ)\left(\mu\right)
=n(n+2)=4×6=24=4.9BM=\sqrt{n\left(n+2\right)}=\sqrt{4\times6} =\sqrt{24} =4.9 BM