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Chemistry Question on Magnetic moment

The spin-only magnetic moment of Hexacyanomanganate(II) ion is.........BM

A

5.90 BM

B

1.73 BM

C

4.90 BM

D

3.87 BM

Answer

5.90 BM

Explanation

Solution

The spin-only magnetic moment is calculated using the formula: μ=n(n+2) BM where n is the number of unpaired electrons. For Mn2+, n=5, so: μ=5(5+2)=35≈5.92 BM\text{The spin-only magnetic moment is calculated using the formula:} \\\ \mu = \sqrt{n(n + 2)} \, \text{BM} \\\ \text{where } n \text{ is the number of unpaired electrons. For } \text{Mn}^{2+}, \, n = 5, \text{ so:} \\\ \mu = \sqrt{5(5 + 2)} = \sqrt{35} \approx 5.92 \, \text{BM}