Question

The spin only magnetic moment of $Fe^{2+}$ ion $(in\, B.M.)$ is approximately

• A. 4
• B. 7
• C. 5
• D. 6

Answer 1

Answer: (C)

5

Answer 2

It has 4 unpaired electrons $\therefore \mu =\sqrt{n(n+2)}$ $=\sqrt{4(4+2)}$ $=\sqrt{24}$ $\mu =4.89\, BM\, \approx 5\, BM$