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Question: The 'spin only' magnetic moment (in units of Bohr magneton, mB) of Ni2+ in aqueous solution would be...

The 'spin only' magnetic moment (in units of Bohr magneton, mB) of Ni2+ in aqueous solution would be (atomic number Ni = 28)

A

2.84

B

4.80

C

0

D

1.73

Answer

2.84

Explanation

Solution

3d8

H2O is weak field ligand ; so it does not compel for pairing of electrons. So,

m = n(n+2)=2(2+2)\sqrt{n(n + 2)} = \sqrt{2(2 + 2)}= 2.84 B.M