Question

The 'Spin only' Magnetic moment for $[Ni(NH_3​)_6​]^{2+}$ is _____ × $10^{−1}$ BM. (given = Atomic number of Ni : 28)

Answer 1

NH$_3$ acts as a weak field ligand with Ni$^{2+}$.
$\text{Ni}^{2+} = 3d^8$

1	1	1	1	1

$\text{No. of unpaired electrons} = 2$
$\mu = \sqrt{n(n+2)} = \sqrt{8} = 2.82 \, \text{BM}$
$28.2 \times 10^{-1} \, \text{BM}$
$x = 28$

Answer 2

NH$_3$ acts as a weak field ligand with Ni$^{2+}$.
$\text{Ni}^{2+} = 3d^8$

1	1	1	1	1

$\text{No. of unpaired electrons} = 2$
$\mu = \sqrt{n(n+2)} = \sqrt{8} = 2.82 \, \text{BM}$
$28.2 \times 10^{-1} \, \text{BM}$
$x = 28$