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Question: The spin magnetic moment of cobalt in the compound \(Hg\lbrack Co(SCN)_{4}\rbrack\) is....

The spin magnetic moment of cobalt in the compound Hg[Co(SCN)4]Hg\lbrack Co(SCN)_{4}\rbrack is.

A

3\sqrt{3}

B

8\sqrt{8}

C

15\sqrt{15}

D

24\sqrt{24}

Answer

15\sqrt{15}

Explanation

Solution

In this complex CO2+CO^{2 +} ion have 3 unpaired electron so spin only magnetic moment will be 3(3+2)\sqrt{3(3 + 2)} i.e., 15 6muB.M.\sqrt{15}\mspace{6mu} B.M.