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Question

Physics Question on Refraction of Light

The speed of light in media ‘A’ and ‘B’ are 2.0 × 1010 cm/s and 1.5 × 1010 cm/s respectively. A ray of light enters from the medium B to A at an incident angle ‘θ’. If the ray suffers total internal reflection, then

A

θ=sin−1(34)θ = sin^{-1} (\frac{3}{4})

B

θ>sin−1(23)θ > sin^{-1} (\frac{2}{3})

C

θ<sin−1(34)θ < sin^{-1} (\frac{3}{4})

D

θ>sin−1(34)θ > sin^{-1} (\frac{3}{4})

Answer

θ>sin−1(34)θ > sin^{-1} (\frac{3}{4})

Explanation

Solution

The correct answer is (D) : θ>sin−1(34)θ > sin^{-1} (\frac{3}{4})
μA=3×1082×108=1.5μ_A = \frac{3 × 10^8}{2 × 10^8} = 1.5
μB=3×1081.5×108=2μ_B = \frac{3 × 10^8}{1.5 × 10^8} = 2
For TIR
θ > i c
θ>sin−1(1.52)θ > sin-^{1} ( \frac{1.5}{2} )
θ>sin−1(34)θ > sin^{-1} (\frac{3}{4} )