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Question

Question: The speed of electrons in the second orbit of Be<sup>3+</sup> ion will be-...

The speed of electrons in the second orbit of Be3+ ion will be-

A

c137\frac{c}{137}

B

2c137\frac{2c}{137}

C

3c137\frac{3c}{137}

D

4c137\frac{4c}{137}

Answer

2c137\frac{2c}{137}

Explanation

Solution

V= c137Zn=c13742=2c137\frac{c}{137} \cdot \frac{Z}{n} = \frac{c}{137} \cdot \frac{4}{2} = \frac{2c}{137}