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Question

Physics Question on Gravitation

The speed of earth?s rotation about its axis is ω\omega. Its speed is increased to xx times to make the effective acceleration due to gravity equal to zero at the equator. Then xx is

A

1

B

8.5

C

17

D

34

Answer

17

Explanation

Solution

Earth rotates about its own axis in 24 h.
So, T = 24 x 60 x 60 s
So, angular speed of earth about its own axis
ω=2πT=2π24×60×60rads1\omega=\frac{2\pi}{T}=\frac{2\pi}{24\times60\times60}rad s^{-1}
At equator, g=gReω2g' = g - R_e\omega'^2
or =gReω2=g - R_e\omega'^2
or ω=gRe=2π84.6×60\omega'=\sqrt{\frac{g}R_e}=\frac{2\pi}{84.6\times60}
= ωω=24×60×6084.6×60=17\frac{\omega'}{\omega}=\frac{24\times60\times60}{84.6\times60}=17
ω=17ω\Rightarrow \omega'=17\omega
So, value of x is 17.