Question

The speed of a wave in a string is 20 m/s and frequency is 50 Hz. The phase difference between two points on the string 10 cm apart will be –

• A. p/2
• B. p
• C. 3p/2
• D. 2p

Answer 1

Answer: (A)

p/2

Answer 2

Df = $\frac{2\pi}{\lambda}$ Dx = $\frac{2\pi}{v}$. n. Dx

= $\frac{2\pi}{20}$ × 50 × $\frac{10}{100}$= $\frac{\pi}{2}$