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Question

Question: The speed of a projectile when it is at its greatest height is \(\frac{1}{2}\) times its initial spe...

The speed of a projectile when it is at its greatest height is 12\frac{1}{2} times its initial speed. The angle of projection is –

A

300

B

600

C

450

D

tan–1(3/4

Answer

600

Explanation

Solution

Q u cosq = u2\frac { \mathrm { u } } { 2 } ̃ cosq = 12\frac { 1 } { 2 } ̃ q = 600.