Question

The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is

• A. $60^\circ$
• B. $15^\circ$
• C. $30^\circ$
• D. $45^\circ$

Answer 1

Answer: (A)

$60^\circ$

Answer 2

Let v be velocity of a projectile at maximum height H. v = cos $\theta$ According to given problem, v = $\frac{ u}{ 2}$ $\therefore \frac{u}{2} = u \, \cos \, \theta \Rightarrow \cos \, \theta = \frac{1}{2}$ $\Rightarrow \theta = 60^\circ$