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Question

Physics Question on System of Particles & Rotational Motion

The speed of a homogenous solid sphere after rolling down an inclined plane of vertical height h form rest without sliding is

A

107gh\sqrt{\frac{10}{7}gh}

B

gh\sqrt{gh}

C

65gh\sqrt{\frac{6}{5}gh}

D

43gh\sqrt{\frac{4}{3}gh}

Answer

107gh\sqrt{\frac{10}{7}gh}

Explanation

Solution

P.E. = total K.E mgh=710mv2mgh=\frac{7}{10}mv^2, v=10gh7v=\sqrt{\frac{10gh}{7}}