Question

The spectral energy distribution of the Sun (temp = 6050 K) has a maximum at 4753 Å. The temperature of a Star for which this maximum is at 9506 Å is –

• A. 6050 K
• B. 3025 K
• C. 12100 K
• D. 24200 K

Answer 1

Answer: (B)

3025 K

Answer 2

From Wien's law

l_max T = b where b = Wien's constant.

b = 2.89 × 10^–3 m K.

Let For Sun l_m1 = 4753 Å and T₁ = 6050 K.

For Starb l_m2 = 9506 Å and T₂ = ?

or l_m2 T₂ = l_m1 T₁

T₂ = $\frac{\lambda_{m_{1}}}{\lambda_{m_{2}}}$× T₁

=$\frac{4753}{9506}$× 6050 = 3025 K.

Temperature of Star =$\begin{matrix} 3025K. \end{matrix}$