Solveeit Logo
Login

Question

Question: The specific resistance of manganin is \(50 \times 10 ^ { - 8 } \mathrm { ohm } \times \mathrm { m ...

The specific resistance of manganin is 50×10−8ohm×m50 \times 10 ^ { - 8 } \mathrm { ohm } \times \mathrm { m } . The resistance of a cube of length 50 cm will be

A

10−6ohm10 ^ { - 6 } \mathrm { ohm }

B

2.5×10−5ohm2.5 \times 10 ^ { - 5 } \mathrm { ohm }

C

10−8ohm10 ^ { - 8 } \mathrm { ohm }

D

5×10−4ohm5 \times 10 ^ { - 4 } \mathrm { ohm }

Answer

10−6ohm10 ^ { - 6 } \mathrm { ohm }

Explanation

Solution

R=ρlA=50×10−8×50×10−2(50×10−2)2=10−6ΩR = \frac { \rho l } { A } = 50 \times 10 ^ { - 8 } \times \frac { 50 \times 10 ^ { - 2 } } { \left( 50 \times 10 ^ { - 2 } \right) ^ { 2 } } = 10 ^ { - 6 } \Omega