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Question: The specific resistance of manganin is 50 × 10<sup>–8</sup>Ωm. The resistance of a manganin cube hav...

The specific resistance of manganin is 50 × 10–8Ωm. The resistance of a manganin cube having length 50cm50cm is

A

10–6Ω

B

2.5 × 10–5Ω

C

10–8Ω

D

5 × 10–4Ω

Answer

10–6Ω

Explanation

Solution

R=ρlA=50×10−8×50×10−2(50×10−2)2=10−6ΩR = \rho\frac{l}{A} = \frac{50 \times 10^{- 8} \times 50 \times 10^{- 2}}{(50 \times 10^{- 2})^{2}} = 10^{- 6}\Omega