Solveeit Logo

Question

Question: The specific heat of hydrogen gas at constant pressure is \(C_{P} = 3.4 \times 10^{3}cal/kg^{o}C\)an...

The specific heat of hydrogen gas at constant pressure is CP=3.4×103cal/kgoCC_{P} = 3.4 \times 10^{3}cal/kg^{o}Cand at constant volume is CV=2.4×103cal/kgoC.C_{V} = 2.4 \times 10^{3}cal/kg^{o}C. If one kilogram hydrogen gas is heated from 10oC10^{o}C to 20oC20^{o}C at constant pressure, the external work done on the gas to maintain it at constant pressure is

A

10510^{5}cal

B

10410^{4}cal

C

10310^{3} cal

D

5×1035 \times 10^{3}cal

Answer

10410^{4}cal

Explanation

Solution

From FLOT

∆Q = ∆U + ∆W

Work done at constant pressure

(ΔW)P=(ΔQ)PΔU(\Delta W)_{P} = (\Delta Q)_{P} - \Delta U

(ΔQ)P(ΔQ)V(\Delta Q)_{P} - (\Delta Q)_{V} (As we know (ΔQ)V=ΔU(\Delta Q)_{V} = \Delta U)

Also (ΔQ)P=mcPΔT(\Delta Q)_{P} = mc_{P}\Delta T and (ΔQ)V=mcVΔT(\Delta Q)_{V} = mc_{V}\Delta T

(ΔW)P=m(cPcV)ΔT(\Delta W)_{P} = m(c_{P} - c_{V})\Delta T

(ΔW)P=1×(3.4×1032.4×103)×10=104cal(\Delta W)_{P} = 1 \times (3.4 \times 10^{3} - 2.4 \times 10^{3}) \times 10 = 10^{4}cal