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Question: The specific conductivity of N/10 KCl solution at \(20ºC\) is \(0.0212ohm^{- 1}cm^{- 1}\) and the re...

The specific conductivity of N/10 KCl solution at 20ºC20ºC is 0.0212ohm−1cm−10.0212ohm^{- 1}cm^{- 1} and the resistance of the cell containing this solution at 20ºC20ºCis 55 ohm. The cell constant is

A

3.324cm−13.324cm^{- 1}

B

1.166cm−11.166cm^{- 1}

C

2.372cm−12.372cm^{- 1}

D

3.682cm−13.682cm^{- 1}

Answer

1.166cm−11.166cm^{- 1}

Explanation

Solution

k=C×lAk = C \times \frac{l}{A}

lA=k×1C=k×R=0.0212×55=1.166cm−1\frac{l}{A} = k \times \frac{1}{C} = k \times R = 0.0212 \times 55 = 1.166cm^{- 1}