Solveeit Logo
Login

Question

Chemistry Question on Electrochemistry

The specific conductivity of N/10KClN / 10 KCl solution at 20∘C20^{\circ} C is 0.0212 ohm−1cm−10.0212 \,ohm ^{-1} cm ^{-1} and the resistance of cell containing this solution at 20∘C20^{\circ} C is 55ohm55 ohm. The cell constant is

A

2.173 cm−12.173\, cm ^{-1}

B

1.166 cm−11.166\, cm ^{-1}

C

4.616 cm−14.616\, cm ^{-1}

D

3.324 cm−13.324\, cm ^{-1}

Answer

1.166 cm−11.166\, cm ^{-1}

Explanation

Solution

We know that specific conductance == cell constant ×\times conductance ⇒\Rightarrow Cell constant = = Resistance ×\times specific conductance =0.0212×55=0.0212 \times 55 =1.166 cm−1=1.166 \,cm ^{-1}