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Chemistry Question on Electrochemistry

The specific conductance of a N/10 KClN / 10 \,KCl at 25∘C25^{\circ} C is 0.0112 ohm−1cm−1.0.0112\, ohm ^{-1} cm ^{-1} . The resistance of cell containing solution at the same temperature was found to be 55 ohm55\, ohm. The cell constant will be

A

0.142 cm−1cm^{-1}

B

0.66 cm−1cm^{-1}

C

0.918 cm−1cm^{-1}

D

1.12 cm−1cm^{-1}

Answer

0.66 cm−1cm^{-1}

Explanation

Solution

We know that specific conductance = Cell constant ×\times conductance ⇒\Rightarrow Cell constant == Resistance ×\times sp. conductance =55×0.0112=0.616 cm−1=55 \times 0.0112=0.616\, cm ^{-1}