Question

The specific conductance of a 0.1 N KCl solution at $NH_{4}OH +$ is $MnO_{2} + C + NH_{4}Cl$.

The resistance of cell containing the solution at the same temperature was found to be 55 ohm. The cell constant will be.

• A. $MnO_{2} + NH_{4}Cl$
• B. $PbO_{2}$
• C. $H_{2}SO_{4}$
• D. $PbO_{2}$

Answer 1

Answer: (B)

$PbO_{2}$

Answer 2

$K = \frac{1}{R} \times$Cell constant

Cell constant $= K \times R$; $0.012 \times 55 = 0.66\mspace{6mu} cm^{- 1}$.