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Question

Chemistry Question on Electrochemistry

The specific conductance (κ)(\kappa ) of an electrolyte of 0.1N0.1\, N concentration is related to equivalent (Λ)(\Lambda ) by the following formula

A

Λ=κ\Lambda=\kappa

B

Λ=10κ\Lambda=10\,\kappa

C

Λ=100κ\Lambda=100\,\kappa

D

Λ=10000κ\Lambda=10000\,\kappa

Answer

Λ=10000κ\Lambda=10000\,\kappa

Explanation

Solution

Equivalent conductance ()=(\wedge)= specific conductance (κ)×o(\kappa) \times o where, o=o \mid= volume in cm3cm ^{3} containing 1g1\, g equivalent of electrolyte 0.1g0.1\, g equivalent is dissolve in =1000cm31g=1000\, cm ^{3} 1\, g equivalent is dissolve in =10000.1cm3=\frac{1000}{0.1} cm ^{3} =10,000cm3=10,000\, cm ^{3} So, =10,000κ\wedge=10,000\, \kappa