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Question: The specific charge of proton is \(9.6 \times 10^{6}Ckg^{- 1}\) then for an *α*-particle it will be...

The specific charge of proton is 9.6×106Ckg−19.6 \times 10^{6}Ckg^{- 1} then for an α-particle it will be

A

38.4×107Ckg−138.4 \times 10^{7}Ckg^{- 1}

B

19.2×107Ckg−119.2 \times 10^{7}Ckg^{- 1}

C

2.4×107Ckg−12.4 \times 10^{7}Ckg^{- 1}

D

4.8×107Ckg−14.8 \times 10^{7}Ckg^{- 1}

Answer

4.8×107Ckg−14.8 \times 10^{7}Ckg^{- 1}

Explanation

Solution

(qm)α=12(qm)p=12×9.6×107=4.8×107Ckg−1\left( \frac{q}{m} \right)_{\alpha} = \frac{1}{2}\left( \frac{q}{m} \right)_{p} = \frac{1}{2} \times 9.6 \times 10^{7} = 4.8 \times 10^{7}Ckg^{- 1}