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Physics Question on Electric Charge

The specific charge of a proton is 9.6×107 C kg−19.6\times10^{7}\,C\,kg^{-1} The specific charge of an alpha particle will be

A

9.6×107 C kg−19.6 \times 10^{7}\,C\,kg^{-1}

B

19.2×107 C kg−119.2 \times 10^{7}\,C\,kg^{-1}

C

4.8×107 C kg−14.8 \times 10^{7}\,C\,kg^{-1}

D

2.4×107 C kg−12.4 \times 10^{7}\,C\,kg^{-1}

Answer

4.8×107 C kg−14.8 \times 10^{7}\,C\,kg^{-1}

Explanation

Solution

For proton, Specific charge =em=9.6×107 C kg−1=\frac{e}{m}=9.6 \times10^{7}\,C\,kg^{-1} For alpha particle, Specific charge =2e4m=12em=12×9.6×107= \frac{2e}{4m} = \frac{1}{2}\frac{e}{m}=\frac{1}{2}\times9.6\times10^{7} =4.8×107 C kg−1=4.8 \times 10^{7}\,C\,kg^{-1}