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Question

Chemistry Question on Structure of atom

The specific charge of a proton is 9.6×107Ckg19.6 \times 10^7 \, C \, kg^{-1}. The specific charge of an alpha particle will be :

A

9.6×107Ckg19.6 \times 10^{7} \,C \, kg^{-1}

B

19.2×107Ckg119.2 \times10^{7}\, C \, kg^{-1}

C

4.8×107Ckg14.8 \times10^{7} \,C \,kg^{-1}

D

2.4×107Ckg12.4 \times10^{7}\, C \,kg^{-1}

Answer

4.8×107Ckg14.8 \times10^{7} \,C \,kg^{-1}

Explanation

Solution

Specific charge on proton =(em)p=\left(\frac{e}{m}\right)_{p} 9.6×107C/kg9.6 \times 10^{7} C / kg specific charge (qm)α=2e4m=12(em)p=12×9.6×107\left(\frac{q}{m}\right)_{\alpha}=\frac{2 e}{4 m} =\frac{1}{2}\left(\frac{e}{m}\right)_{p}=\frac{1}{2} \times 9.6 \times 10^{7} =4.8×107C/kg=4.8 \times 10^{7} C / kg