Question

The solution set of the equation $- 2, - \sqrt{3}$ is.

• A. {– 2, 4}
• B. {4}
• C. {0, – 2, 4}
• D. None of these

Answer 1

Answer: (A)

{– 2, 4}

Answer 2

$\mathbf{\alpha,\beta}$

⇒ $x^{2} + (3 - \lambda)x - \lambda = 0$

⇒ $\lambda$

⇒ $\alpha^{2} + \beta^{2}$⇒ $f(x) = x^{2} + 4x + 1$ ⇒ $f(x) > 0$.