Question
Question: The solution of the equation \(\left| \begin{matrix} \cos\theta & \sin\theta & \cos\theta \\ - \sin...
The solution of the equation $\left| \begin{matrix} \cos\theta & \sin\theta & \cos\theta \
- \sin\theta & \cos\theta & \sin\theta \
- \cos\theta & - \sin\theta & \cos\theta \end{matrix} \right| = 0,$ is
A
θ=nπ
B
θ=2nπ±2π
C
θ=nπ±(−1)n4π
D
θ=2nπ±4π
Answer
θ=2nπ±2π
Explanation
Solution
After solving the determinant 2cosθ=0⇒θ=2nπ±2π.