Question

The solution of the equation $\frac{p}{q}$ will be.

• A. 2, –1
• B. 0, –1, $x^{2} + px + q = 0$
• C. $p^{3} + q^{2} - q(3p + 1) = 0$
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

$x + \frac { 1 } { x } = 2 \Rightarrow x + \frac { 1 } { x } - 2 = 0$ $\mathbf{x}^{\mathbf{3}}\mathbf{-}\mathbf{64 = 0}$

⇒ $\alpha,\beta,\gamma$ ⇒$x^{3} + 4x + 1 = 0$⇒ $(\alpha + \beta)^{- 1} + (\beta + \gamma)^{- 1} + (\gamma + \alpha)^{- 1} =$.