Question

The solution of the differential equation

$\frac{dy}{dx} = \frac{\sin y + x}{\sin 2y - x\cos y}$ is

• A. sin²y= x sin y + $\frac{x^{2}}{2} + c$
• B. sin²y = x sin y – $\frac{x^{2}}{2} + c$
• C. sin²y = x + sin y + $\frac{x^{2}}{2} + c$
• D. sin²y = x – sin y + $\frac{x^{2}}{2} + c$

Answer 1

Answer: (A)

sin²y= x sin y + $\frac{x^{2}}{2} + c$

Answer 2

cosy $\frac{dy}{dx}$= $\frac{\sin y + x}{2\sin y–x}$ put sin y = t