Question

The solution of the differential equation $\frac{y dx + x dy}{y dx - x dy} = \frac{x^{2} e^{xy}}{y^{4}}$ satisfying $y(0) = 1$, is :

• A. $x^3 = 3y^3 (1 - e^{-xy} )$
• B. $x^3 = 3y^3 ( - 1 + e^{xy} )$
• C. $x^3 = 3y^3 (1 - e^{xy} )$
• D. $x^3 = 3y^3 (- 1 + e^{-xy} )$

Answer 1

Answer: (A)

$x^3 = 3y^3 (1 - e^{-xy} )$

Answer 2

Answer (a) $x^3 = 3y^3 (1 - e^{-xy} )$