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Question

Mathematics Question on Differential equations

The solution of the differential equation dydx=(x+y)2\frac{dy}{dx} = (x+y)^2 is

A

tan⁡−1(x+y)=x+c\tan^{-1}(x+y) = x + c

B

cot⁡−1(x+y)=c\cot^{-1}(x+y) = c

C

tan⁡−1(x+y)=0\tan^{-1}(x+y) =0

D

cot⁡−1(x+y)=x+c\cot^{-1}(x+y) = x + c

Answer

tan⁡−1(x+y)=x+c\tan^{-1}(x+y) = x + c

Explanation

Solution

The correct answer is (A) : tan⁡−1(x+y)=x+c\tan^{-1}(x+y) = x + c.