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Mathematics Question on Solutions of Differential Equations

The solution of the differential equation dydx+y=3exy3\frac{dy}{dx}+y=3e^xy^3 is :

A

1y2=6ex+ce2x\frac{1}{y^2}=6e^x+ce^{2x}

B

1y2=6e−x+ce2x\frac{1}{y^2}=6e^{-x}+ce^{2x}

C

1y2=6ex+ce−2x\frac{1}{y^2}=6e^x+ce^{-2x}

D

1y2=6e−x+ce−2x\frac{1}{y^2}=6e^{-x}+ce^{-2x}

Answer

1y2=6ex+ce2x\frac{1}{y^2}=6e^x+ce^{2x}

Explanation

Solution

The correct option is(A):1y2=6ex+ce2x\frac{1}{y^2}=6e^x+ce^{2x}.