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Question: The solution of tan<sup>–1</sup> 2x + tan<sup>–1</sup> 3x =\(\frac { \pi } { 4 }\)is-...

The solution of tan–1 2x + tan–1 3x =π4\frac { \pi } { 4 }is-

A

1/6

B

–1

C

{16,−1}\left\{ \frac { 1 } { 6 } , - 1 \right\}

D

½

Answer

1/6

Explanation

Solution

tan–1 π4\frac { \pi } { 4 }

Ž 5x = 1 – 6x2

Ž 6x2 + 5x – 1 = 0

Ž x = –1, 1/6

But sum of the –ve number cannot be p/4, hence x = 1/6 is

only solution.