Question
Question: The solution of equation \(x^{2} + px + q = 0\)+\(x^{2} + qx + p = 0\)+\(p + q + 1 =\) is....
The solution of equation
x2+px+q=0+x2+qx+p=0+p+q+1= is.
A
x2+ax+10=0
B
x2+bx−10=0
C
a2−b2
D
x2−11x+a
Answer
x2+ax+10=0
Explanation
Solution
We have x2+ax+b=0= x2+bx+a=0
(a+b) =x(3/4)(log2x)2+(log2x)−5/4=2
a>0,b>0,c>0ax2+bx+c=0
k 2x2−kx+x+8=0
2x2+3x+1=0l,m,n.