Question

The solution of differential equation $\frac { d y } { d x } + \sin ^ { 2 } y = 0$ is

• A. $y + 2 \cos y = c$
• B. $y - 2 \sin y = c$
• C. $x = \cot y + c$
• D. $y = \cot x + c$

Answer 1

Answer: (C)

$x = \cot y + c$

Answer 2

$\frac { d y } { d x } + \sin ^ { 2 } y = 0$ ⇒ $- \frac { d y } { \sin ^ { 2 } y } = d x$.

On integrating, we get